We all know the traditional formula to compute compound interest.

CI = P*(1+R/100)^N - P

This calculation gets very tedious when N>2 (more than 2 years). The method suggested below is a very simple way to get CI/Amount after 'N' years.

You need to recall the old Pascal's Triangle in following way:

Code:

Number of Years (N)

-------------------

1 1

2 1 2 1

3 1 3 3 1

4 1 4 6 4 1

. 1 .... .... ... ... 1

Example: P = 1000, R=10 %, and N=3 years. What is CI & Amount?

Step 1: 10% of 1000 = 100, Again 10% of 100 = 10 and 10% of 10 = 1

We did this three times becoz N=3.

Step 2:

Now Amount after 3 years = 1 * 1000 + 3 * 100 + 3 * 10 + 1 * 1 = Rs.1331/-

The co-efficients - 1,3,3,1 are lifted from the pascal's triangle above.

Step 3:

CI after 3 years = 3*100 + 3*10 + 3*1 = Rs.331/- (leaving out first term in step 2)

If N =2, we would have had, Amt = 1 * 1000 + 2 * 100 + 1 * 10 = Rs. 1210/-

CI = 2 * 100 + 1* 10 = Rs. 210/-

This method is extendable for any 'N' and it avoids calculations involving higher powers on 'N' altogether!

A variant to this short cut can be applied to find depreciating value of some property. (Example, A property worth 100,000 depreciates by 10% every year, find its value after 'N' years).

Hai, This trick was amazing and it helped me a lot... Thanks.

ReplyDeletePlease correct

ReplyDeleteStep 3:

3*100 + 3*10 + 1*1 = Rs.331/-

3,3,3 instead of 3,3,1

really a very good methood.... which we studied in class cbsc class 9th but still not able to apply that........

ReplyDeleteVery nice.Thank you.

ReplyDeleteNice method.Thanks for helping me out

ReplyDeleteThank you

ReplyDeleteThis trick is Amazing! Could you please tell, how to find Rate, Principle or time through this method?

ReplyDelete